Update chapter4_questions&keywords.md

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Yiyuan Yang
2021-05-24 09:27:40 +08:00
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@@ -101,7 +101,7 @@
$$
带入第三个式子,可以将其化简为:
$$
\nabla_{\theta}J(\theta) =E_{\tau \sim p_{\theta}(\tau)}[{\nabla}_{\theta}logp_{\theta}(\tau)r(\tau)] = E_{\tau \sim p_{\theta}}[(\nabla_{\theta}log\pi_{\theta}(a_t|s_t))(\sum_{t=1}^Tr(s_t,a_t))] = \frac{1}{N}\sum_{i=1}^N[(\sum_{t=1}^T\nabla_{\theta}log \pi_{\theta}(a_{i,t}|s_{i,t}))(\sum_{t=1}^Nr(s_{i,t},a_{i,t}))]
\nabla_{\theta}J(\theta) =E_{\tau \sim p_{\theta}(\tau)}[{\nabla}_{\theta}logp_{\theta}(\tau)r(\tau)] = E_{\tau \sim p_{\theta}}[(\nabla_{\theta}log\pi_{\theta}(a_t|s_t))(\sum_{t=1}^Tr(s_t,a_t))] \\ = \frac{1}{N}\sum_{i=1}^N[(\sum_{t=1}^T\nabla_{\theta}log \pi_{\theta}(a_{i,t}|s_{i,t}))(\sum_{t=1}^Nr(s_{i,t},a_{i,t}))]
$$
- 高冷的面试官:可以说一下你了解到的基于梯度策略的优化时的小技巧吗?